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I have a Weaver 20 MOA 1 piece base on my Stevens LA. I question whether it is 20 or some far less MOA base. To the naked eye it is fairly flat/level front to back. When measured with calipers there is only .04 difference front to back. Is that 20 MOA? I could spend a week trying to calculate it but was hoping someone had a 1 piece base laying around to confirm. I do have a 20 MOA on my WBY MKV, and you can't see the cant from across the room. Any help would be appreciated.
Distance between your measurements? LA Savage is ~7.5" long, 20 MOA is ~.0058" per inch. 7.5 X .0058 = ~.043...sounds about right depending on where you measured.
Between mounting holes so roughly 5.0"
Wouldn't 20 Moa be around .017 per inch? If that is that the case then my bases only has about 10 Moa, but like I said I need help and need to understand the math better.
KRP is spot on.
Here's how to derive his answer:
reference: http://www.mathsisfun.com/sine-cosine-tangent.html
the tangent of an angle is = length of the opposite side / length of the adjacent side.
http://www.mathsisfun.com/algebra/im...an-divides.gif
Since we are discussing a slope (angle) of 20 minutes of angle, and there are 60 minutes in a degree, we know that this angle equals .33333o
So: Tan (.33333o)=opposite/1 inch
Using a calculator we find that Tan (.33333o)=0.0058178
So: for every 1 inch of length, a 20 minute of angle slope will rise (or fall) .005818 inches.
I love math in real life!!